Optimal. Leaf size=116 \[ -\frac {\sqrt {2} a e^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e}+\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}+\frac {2 a e^2 \sqrt {e \cot (c+d x)}}{d}-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d} \]
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Rubi [A]
time = 0.11, antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 3, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {3609, 3613,
214} \begin {gather*} -\frac {\sqrt {2} a e^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e} \cot (c+d x)+\sqrt {e}}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}+\frac {2 a e^2 \sqrt {e \cot (c+d x)}}{d}-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 214
Rule 3609
Rule 3613
Rubi steps
\begin {align*} \int (e \cot (c+d x))^{5/2} (a+a \cot (c+d x)) \, dx &=-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d}+\int (e \cot (c+d x))^{3/2} (-a e+a e \cot (c+d x)) \, dx\\ &=-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d}+\int \sqrt {e \cot (c+d x)} \left (-a e^2-a e^2 \cot (c+d x)\right ) \, dx\\ &=\frac {2 a e^2 \sqrt {e \cot (c+d x)}}{d}-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d}+\int \frac {a e^3-a e^3 \cot (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx\\ &=\frac {2 a e^2 \sqrt {e \cot (c+d x)}}{d}-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d}-\frac {\left (2 a^2 e^6\right ) \text {Subst}\left (\int \frac {1}{2 a^2 e^6-e x^2} \, dx,x,\frac {a e^3+a e^3 \cot (c+d x)}{\sqrt {e \cot (c+d x)}}\right )}{d}\\ &=-\frac {\sqrt {2} a e^{5/2} \tanh ^{-1}\left (\frac {\sqrt {e}+\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}+\frac {2 a e^2 \sqrt {e \cot (c+d x)}}{d}-\frac {2 a e (e \cot (c+d x))^{3/2}}{3 d}-\frac {2 a (e \cot (c+d x))^{5/2}}{5 d}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 0.21, size = 68, normalized size = 0.59 \begin {gather*} -\frac {2 a e (e \cot (c+d x))^{3/2} \left (3 \cot (c+d x) \, _2F_1\left (-\frac {5}{4},1;-\frac {1}{4};-\tan ^2(c+d x)\right )+5 \, _2F_1\left (-\frac {3}{4},1;\frac {1}{4};-\tan ^2(c+d x)\right )\right )}{15 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(318\) vs.
\(2(95)=190\).
time = 0.42, size = 319, normalized size = 2.75
method | result | size |
derivativedivides | \(-\frac {a \left (\frac {2 \left (e \cot \left (d x +c \right )\right )^{\frac {5}{2}}}{5}+\frac {2 e \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{3}-2 e^{2} \sqrt {e \cot \left (d x +c \right )}+2 e^{3} \left (\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 e}-\frac {\sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}\right )\right )}{d}\) | \(319\) |
default | \(-\frac {a \left (\frac {2 \left (e \cot \left (d x +c \right )\right )^{\frac {5}{2}}}{5}+\frac {2 e \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{3}-2 e^{2} \sqrt {e \cot \left (d x +c \right )}+2 e^{3} \left (\frac {\left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 e}-\frac {\sqrt {2}\, \left (\ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{8 \left (e^{2}\right )^{\frac {1}{4}}}\right )\right )}{d}\) | \(319\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.53, size = 101, normalized size = 0.87 \begin {gather*} -\frac {{\left (15 \, {\left (\sqrt {2} \log \left (\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right ) - \sqrt {2} \log \left (-\frac {\sqrt {2}}{\sqrt {\tan \left (d x + c\right )}} + \frac {1}{\tan \left (d x + c\right )} + 1\right )\right )} a - \frac {60 \, a}{\sqrt {\tan \left (d x + c\right )}} + \frac {20 \, a}{\tan \left (d x + c\right )^{\frac {3}{2}}} + \frac {12 \, a}{\tan \left (d x + c\right )^{\frac {5}{2}}}\right )} e^{\frac {5}{2}}}{30 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 181 vs.
\(2 (88) = 176\).
time = 3.29, size = 181, normalized size = 1.56 \begin {gather*} \frac {15 \, {\left (\sqrt {2} a \cos \left (2 \, d x + 2 \, c\right ) e^{\frac {5}{2}} - \sqrt {2} a e^{\frac {5}{2}}\right )} \log \left ({\left (\sqrt {2} \cos \left (2 \, d x + 2 \, c\right ) - \sqrt {2} \sin \left (2 \, d x + 2 \, c\right ) - \sqrt {2}\right )} \sqrt {\frac {\cos \left (2 \, d x + 2 \, c\right ) + 1}{\sin \left (2 \, d x + 2 \, c\right )}} + 2 \, \sin \left (2 \, d x + 2 \, c\right ) + 1\right ) + 4 \, {\left (18 \, a \cos \left (2 \, d x + 2 \, c\right ) e^{\frac {5}{2}} + 5 \, a e^{\frac {5}{2}} \sin \left (2 \, d x + 2 \, c\right ) - 12 \, a e^{\frac {5}{2}}\right )} \sqrt {\frac {\cos \left (2 \, d x + 2 \, c\right ) + 1}{\sin \left (2 \, d x + 2 \, c\right )}}}{30 \, {\left (d \cos \left (2 \, d x + 2 \, c\right ) - d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} a \left (\int \left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}}\, dx + \int \left (e \cot {\left (c + d x \right )}\right )^{\frac {5}{2}} \cot {\left (c + d x \right )}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.98, size = 144, normalized size = 1.24 \begin {gather*} \frac {2\,a\,e^2\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{d}-\frac {2\,a\,e\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{3\,d}-\frac {2\,a\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{5/2}}{5\,d}+\frac {{\left (-1\right )}^{1/4}\,a\,e^{5/2}\,\mathrm {atan}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,1{}\mathrm {i}}{\sqrt {e}}\right )}{d}-\frac {{\left (-1\right )}^{1/4}\,a\,e^{5/2}\,\mathrm {atanh}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{\sqrt {e}}\right )}{d}+\frac {{\left (-1\right )}^{1/4}\,a\,e^{5/2}\,\mathrm {atan}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{\sqrt {e}}\right )\,\left (1+1{}\mathrm {i}\right )}{d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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